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24 votes
24 votes
What is the slope of a line passing through (-5, 5) and
(-4, 10)?

User Blessy
by
3.1k points

2 Answers

20 votes
20 votes

Answer:

Slope = 5

Explanation:

Slope:

(-5,5) ; x₁ = -5 & y₁ = 5

(-4, 10) ; x₂ = -4 & y₂ = 10


\sf \boxed{\bf Slope = (y_2-y_1)/(x_2-x_1)}


\sf =(10-5)/(-4-[-5])\\\\ =(10-5)/(-4+5)\\\\=(5)/(1)\\\\= 5

User Independent
by
3.2k points
16 votes
16 votes

Answer:

5

Explanation:

Formula for finding slope:


(y1 - y2)/(x1 - x2)

Slope of line passing through (-5,5) and (-4,10)

=


(5 - 10)/( - 5 - ( - 4)) \\ = ( - 5)/( - 5 + 4) \\ = ( - 5)/( - 1) \\ = 5

User Chrisofspades
by
2.9k points