Question

The perimeter of a rectangle is 44 centimeters. If the length is 10 centimeters, find the value.

Answer 1

12 centimeters is the width value.

Explanation:

Note that too solve the perimeter of the rectangle, you must use the following equation:

P (Perimeter) = 2(length) + 2(width)

or

P = 2(l) + 2(w)

Note that length (l) is given to you, and it's measurement is 10. Plug in 10 for length. Also note that perimeter (P) is given to us, and is 44.

44 = 2(10) + 2(w)

Simplify. First multiply.

44 = 2(10) + 2w

44 = 20 + 2w

Isolate the variable, w. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS*.

First, subtract 20 from both sides.

44 (-20) = 20 (-20) + 2w

44 - 20 = 2w

24 = 2w

Isolate the variable, w. Divide 2 from both sides.

(24)/2 = (2w)/2

w = 24/2

w = 12

12 centimeters is the width value.

~

-------------------------------------------------------------------------------------------------------------

*Note:

PEMDAS =

Parenthesis

Exponents (& roots)

Multiplication

Division

Addition

Subtraction

& is the order that you solve.

-------------------------------------------------------------------------------------------------------------

Answer 2

12 cm is the width

Explanation:

The perimeter of a rectangle is given by

P = 2(l+w)

We know the perimeter is 44 and the length is 10

44 = 2 (10+w)

Divide each side by 2

44/2 = 2/2 (10+w)

22 = 10+w

Subtract 10 from each side

22-10 = 10-10 +w

12 = w

The width is 12