Question

A rectangle has an area of 717.8m2.

One of the sides is 7.4m in length.
Work out the perimeter of the rectangle.
please help me

Answer 1

The perimeter of the rectangle is
`208.8\ m`

Explanation:

step 1

Find the width of the rectangle

we know that

The area of rectangle is equal to

`A=LW`

we have

`A=717.8\ m^(2)`

`L=7.4\ m`

substitute and solve for W

`717.8=7.4W`

`W=717.8/7.4=97\ m`

step 2

Find the perimeter

The perimeter of rectangle is equal to

`P=2(L+W)`

we have

`W=97\ m`

`L=7.4\ m`

substitute

`P=2(7.4+97)=208.8\ m`