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How many moles of potassium iodide, KI, are in 50 grams?

User Loupi
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2 Answers

3 votes

Final answer:

To find the number of moles of potassium iodide in 50 grams, calculate using the molar mass of KI, which is 166.0 g/mol. The calculation shows that there are approximately 0.301 moles of KI in 50 grams.

Step-by-step explanation:

The question asks how many moles of potassium iodide, KI, are in 50 grams. To find the number of moles, we use the formula:

number of moles = mass (g) / molar mass (g/mol)

First, we need to determine the molar mass of potassium iodide (KI). Potassium (K) has an atomic mass of approximately 39.1 g/mol and iodine (I) has an atomic mass of approximately 126.9 g/mol. Therefore, the molar mass of KI is:

39.1 g/mol (K) + 126.9 g/mol (I) = 166.0 g/mol (KI)

Now, we can calculate the number of moles of KI in 50 grams:

number of moles = 50 g / 166.0 g/mol

The calculation gives us:

number of moles = 0.301 moles of KI

Thus, there are approximately 0.301 moles of potassium iodide in 50 grams.

User Radmila
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5.1k points
2 votes

Answer:

0.30 mol.

Step-by-step explanation:

  • The no. of moles of any compound is the mass of the compound divided by the molar mass of the compound:

no. of moles (n) = mass/molar mass = (50.0 g)/(166.0 g/mol) = 0.30 mol.

User Ayrat
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5.0k points