Answer:
e = 2/5
a = 5
b = √21
c = 2
Explanation:
The first step is to write the given polar equation in standard form by dividing the numerator and denominator by 5;
![r=((21)/(5) )/(1-(2)/(5)costheta )](https://img.qammunity.org/2020/formulas/mathematics/high-school/2z8e3al8ddif9io3tzkmb8vl1hia42nsmc.png)
The eccentricity of this conic section is thus 2/5, the coefficient of cos theta. Nevertheless, the eccentricity of a conic section can also be evaluated using the equation;
![e=(c)/(a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/vnvwrfyc1mac98k88p42sfnfovkcia45fo.png)
This implies that ;
a = 5
c = 2
The value of b is determined using the relation;
![b^(2)=a^(2)-c^(2) \\b=√(25-4) \\b=√(21)](https://img.qammunity.org/2020/formulas/mathematics/high-school/usmljrqa7v1449smomkh3soi9ibu74o4z0.png)