Question

The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is

Answer 1

Explanation:

The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is

`x=√((-y-10)(y+2)) +5,-√((-y-10)(y+2)) +5`

Steps:

(x-5)²+(y+6)²=4²

Rewrite:

(x-5)²+(y-(-6))²=4²

Answer 2

(5, -6)

Explanation: