Question

A rocket launched vertically from the ground with an initial veocity of 56ft?sec (A) Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched.

(B)Graph h(t) on the coordinate plane.
(C) Use your graph from Part 3(b) to determine the rocket’s maximum height, the amount of time it took to reach its maximum height, and the amount of time it was in the air.
Answer:
PLZZZZZZZZ HELP!!!!!!!!!!ASAP

Answer 1

• h(t) = -16t^2 +56t
• max height: 49 ft
• time to max height: 1.75 s

Explanation:

Ballistic motion is usually modeled by the quadratic ...

h(t) = -1/2g·t^2 +v0·t +h0

where g is the acceleration due to gravity, v0 is the initial upward velocity, and h0 is the initial height. Here, we have g = 32 ft/s^2, v0 = 56 ft/s, h0 = 0.

(A) That makes our quadratic function be ...

h(t) = -16t^2 +56t

(B) see the attachment for a graph

(C) see the attachment for the time and height at the highest point.