Answer:
(2, 8)
Explanation:
A hole occurs when the denominator is equal to 0. In this case, the denominator equals zero when x = 2.
Next, we must find the value of y by factoring the numerator and simplifying:
![(x^(2) +4x-12)/(x-2) = ((x-2)(x+6))/(x-2) = x+6](https://img.qammunity.org/2020/formulas/mathematics/high-school/nm03hcekwl901k5ardbmgjwuvad5v48k53.png)
Then plug in 2 for x:
2 + 6 = 8.
Therefore, there is a hole at (2, 8)