Question

Please help me?

y=2(x-5)^2-8
Solve the equation for when y=10, show your work algebraically.

Answer 1

Explanation:

I've included a graph to confirm the solution.

10 = 2(x - 5)^2 - 8 Subtract 10 from both sides.

10-10 = 2(x-5)^2 - 8 - 10 Switch

2(X - 5)^2 - 18 = 0 Divide through by 2

2(x - 5)^2/2 - 18/2 =0

(x - 5)^2 - 9 = 0 Expand the brackets.

x^2 - 10x + 25 - 9 = 0 Collect like terms

x^2 - 10x + 16 = 0 Factor

(x - 8)(x - 2) = 0

x = 8

x = 2

red: 2(x - 5)^2 -8

green: y = 10