Question

The truth set of x2 + x = 8

Answer 1

Answer:
`\bold{x=(-1+ √(33))/(2)\qquad and\qquad x=(-1- √(33))/(2)}`

Explanation:

`x^2+x=8\\\\\text{subtract 8 from both sides:}\\x^2+x-8=0\qquad \rightarrow \qquad a=1, b=1, c=-8\\\\\\\text{Use the quadratic formula to solve for x:}\\x = (-b\pm √(b^2-4ac))/(2a)\\\\\\x = (-(1)\pm √((1)^2-4(1)(-8)))/(2(1))\\\\\\.\ =(-1\pm √(1+32))/(2)\\\\\\.\ =(-1\pm √(33))/(2)\\\\\\x=(-1+ √(33))/(2)\qquad and\qquad x=(-1- √(33))/(2)`