Question

Consider this function.

f(x) = 6x2 − 11x − 10.

What are the zeros of the function? A) x = 5/2 and x = − 2/3 B) x = − 5/2 and x = 2/3 C) x = 2/5 and x = − 2/3 D) x = − 2/5 and x = 3/2

Answer 1

2, 3, 5

Explanation:

just took it

Answer 2

Answer: A)
`x=(5)/(2)` and
`x=-(2)/(3)`

Explanation:

Make the quadratic function
`f(x)=6x^2-11x-10` equal to zero:

`6x^2-11x-10=0`

Having the form
`ax^2+bx+c=0`, the zeros can be calculated with a formula called "Quadratic formula":

`x=(-b\±√(b^2-4ac))/(2a)`

Then:

Identify a, b and c:

`a=6\\b=-11\\c=-10`

Finally, substitute them into the Quadratic formula:

`x=(-(-11)\±√((-11)^2-4(6)(-10)))/(2(6))\\\\x=(11\±√(361))/(12)\\\\x=-(2)/(3)\\\\x=(5)/(2)`