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How much p² – q² + 2pq is less than -2p² -2q² + 7pq +10 ?

1 Answer

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Answer: 3p² + q² - 5pq - 10 < 0

Explanation:

p² - q² + 2pq < -2p² - 2q² + 7pq + 10

since you didn't specify what to solve for, move everything from the right side to the left side of the inequality symbol using inverse operations.

(p² + 2p²) + (- q² + 2q²) + (2pq - 7pq) + (- 10) < 0

3p² + q² + -5pq + -10 < 0

3p² + q² - 5pq - 10 < 0

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