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What is the range of the function y = -x ^2 + 1?

y ≤ -1
y ≥ -1
y ≤ 1
y ≥ 1

2 Answers

1 vote


y \leqslant - 1

User Artier
by
6.0k points
2 votes

Answer:


y\leq -1

Explanation:


y = -x ^2 + 1

Range is the set of y values for which the function is defined

To find out the range we look at the value of k in the vertex


y = -x ^2 + 1

General vertex form is :
y=a(x-h)^2+k

where (h,k) is the vertex that is maximum when a is negative

From the given equation the value of k= -1

The graph reaches the maximum value at y=-1

So range is
y\leq -1

User Little Endian
by
6.0k points