Question

Given the following equation:
`y = 3(x+8)^(2) + 6`

What would be the vertex (h,k)
Vertex = (_,_)

Answer 1

The vertex of given equation is (-8,6).

Explanation:

We have given an equation in vertex form.

y = 3(x+8)²+6

We have to find vertex of the given equation.

y = a(x-h)²+k where (h,k) denotes vertex of the equation.

y = 3(x-(-8))²+6

Comparing both equations, we have

h = -8 and k = 6

hence, the vertex of given equation is (-8,6).

Answer 2

Answer:
`h=-8\\k=6`

Explanation:

By definition, we know that the quadratic equation in the vertex form is:

`y=a(x-h)^(2)+k`

Where (h, k) is the vertex.

We have thefollowing equation given in the problem:

`y=3(x+8)^(2)+6`

Therefore, you can conclude that the vertex is (-8,6).

Therefore the answer is:

`h=-8\\k=6`