Question

What is the point-slope equation of a line with slope -3 that contains the point (-8,-4)?​

Answer 1

y+4 = -3(x+8)

Explanation:

We have given slope of a line and a point that passes through the line.

slope = m = -3 and (x₁,y₁) = (-8,-4)

We have to find the point-slope form of the line.

y-y₁ = m(x-x₁) where m is slope and (x₁,y₁) is a point that passes through the line.

Putting given values in point-slope form ,we have

y-(-4) = -3(x-(-8))

y+4 = -3(x+8) is point slope form of line having slope equal to -3 and that passes through the point (-8,-4).

Answer 2

Answer:
`(y+4)=-3(x+8)`

Explanation:

The equation of the line is point-slope form is:

`(y-y_1)=m(x-x_1)`

Where m is the slope of the line and (
`x_1,y_1`) is a point of the line.

You know that the slope is -3 and the problem gives you the point (-8,-4), therefore you only need to substitute them into the equation shown above.

Then, you obtain:

`(y-(-4))=-3(x-(-8))`

`(y+4)=-3(x+8)`