Answer:
![\large\boxed{A=171.555\ in^2}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z87tdl6d2x4uq5o57ycutz15thpqj77tmj.png)
Explanation:
We have the right triangle and the trapezoid.
The formula of an area of a right triangle:
![A_(triangle)=(ab)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m6cag7333vkeih2rwdv5p319deek10av4k.png)
a, b - legs
We have the length of the legs 12in and 13.42 in. Substitute:
![A_(triangle)=((12)(13.42))/(2)=80.52\ in^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1iw0r739vjr8vwf57ah619y7mri0w8klsm.png)
The formula of an area of a trapezoid:
![A_(trapezoid)=((b_1+b_2)h)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4zs6eozn19ixuuea7t6oetk37or0br4bng.png)
b₁, b₂ - bases
h - height
We have the length of the bases 18in and 11.75in and the length of the height 6.12in. Substitute:
![A_(trapezoid)=((18+11.75)(6.12))/(2)=((29.75)(6.12))/(2)=91.035\ in^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pyzdwr9v648bcajdmx9j8qyofbrjiszlxt.png)
The area of the figure:
![A=A_(triangle)+A_(trapezoid)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i22rtl0bscsvdsggq23u9nuckjohl2jyey.png)
Substitute:
![A=80.52+91.035=171.555\ in^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kio0o45rpyawiwvlaew08yib0cv0lvnv4n.png)