Question

How many acetone molecules are in a bottle of acetone with a volume of 445 mL ? (density of acetone = 0.788 g/cm3).

Answer 1

The number of molecules would be 2.5*10^24 molecules

Step-by-step explanation:

In order to find the molecules, first you need the molecular formula and weight of acetone, CH3COCH3 which is 58 g/ mole.

Let us determine mass of acetone

300mL= 300cm^3*.788g/cm^3= 236.4 g

Finding number of moles

236.4g/ 58g/mol=4.08 moles

Now the number of molecules.

4.08moles *6.02*10^23 molecules/ mole

which are 2.5*10^24 molecules

Answer 2

Hello!

The answer is:
`3.63x10^(24)particles`

Why?

First, we need to calculate the molecular weight of the acetone (CH3COCH3)

So,

`C=12.011g/mol\\O=15.99g/mol\\H=1.008g/mol`

Then,

`CH3COCH3=12.011+(1.008)*3+12.011+15.999+12.011+(1.008)*3=58.08g/mol`

Second, we need to calculate the mass of the acetone in the bottle

We need to remember that
`1cm^(3)=1mL`

So,

`445cm^(3)*(0.788g)/(cm^(3))=350.66g`

Third, we need to calculate the number of moles:

`350.66g*(1mol)/(58.08g)=6.03moles`

Fourth, we need to calculate the number of atoms:

Remember,
`1 mol=6.022x10^(23)particles`

Therefore,

`6.03moles*(6.022x10^(23)particles )/(1mol)=3.63x10^(24)particles`

Have a nice day!