QUESTION 1
Let the number be
.
If this number is decreased by 32 and the result is -58, then we can write the following equation and solve for
.
.
Group the similar terms to get;


The number is -26.
QUESTION 2
The product of 14 and
is
If the product is -28, then the require algebraic equation is
QUESTION 3
Let the number be
.
Four times this number is
.
The number increased by 78 is
.
If four times the number is the same as the number increased by 78, then we write and solve the equation;

Group the similar terms;

Simplify

Divide both sides by 3;


The number is 26
QUESTION 4
Let
represent the price of the blue bike and
represent the price of the red bike.
Then we can write the following two equations and solve simultaneously.


We substitute equation (1) into equation (2) to obtain;

Group like terms;

Simplify;

Divide both sides by 2

The red bike is $157
and
The blue bike is 157-14=$143
QUESTION 5
Let
represent the age of Alex and
represent the age of his sister. Then;


Put equation (1) into equation (2) to get;




Alex is 13+6=19 years old.
QUESTION 6
Let
represent Mrs computer's age and
represent Mousy's age. Then;


Put equation (1) into equation (2).




Mousy is 13 years old.
QUESTION 7.
Let Mike be
years and Tom be
years.
Then;


Put equation (1) into equation (2) and solve.





Mike is 2(20)+5=45 years old.
QUESTION 8
Let the consecutive integers be

The sum of the second and third is 17 gives the equation;

The second choice is correct
QUESTION 9
Let the consecutive integers be

Their sum being 108 gives the equation

Regroup

Simplify the LHS

Factor the LHS

Correct choice is A
QUESTION 10
Let the two consecutive odd integers be;

The sum being 72 gives the equation;

Simplify the first two terms
