219,275 views
45 votes
45 votes
I need help

are they no solution or infinite solutions?
I'm getting ready for high school so I'm reviewing 8th grade math.

I need help are they no solution or infinite solutions? I'm getting ready for high-example-1
User Nithin Varghese
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2.6k points

1 Answer

11 votes
11 votes

Answer:

1. No.

2. Yes, there is no solution here.

Explanation:

The former:


8(5x - 3) = 6(-3x - 4); \\ 8 * 5x - 8 * 3 = 6 * (-3x) - 6 * 4; \\ 40x - 24 = -18x - 24; \\ 40x + 18x = -24 + 24; \\ 58x = 0; \\ x = 0.


\{0\} is our set of solutions.

The latter:


3x - 13 = 7(x + 2) - 4(x - 7); \\ 3x - 13 = 7x + 7 * 2 - 4x - 4 * (-7); \\ 3x - 13 = 7x + 14 - 4x + 28; \\ 7x - 4x - 3x = -13 - 14 - 28;\\ 0x = 55; \\ x \in \emptyset.

In other words, there is not any solution from the set of real numbers that suits us.

User Gaurav Shrivastava
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3.1k points