Question

I don't know how to solve this at all, i just need some help on how to figure it out. Thanks!

Answer 1

The answer is :
`\boxed {(3)/(z-3)}`

Remember that dividing fractions is the same as multiplying the 1st fraction by the reciprocal of the other.

`\mathsf {(1)/(z) / (z-3)/(3z)}`

`\mathsf {(1)/(z) * (3z)/(z - 3)}`

`\mathsf {(3)/(z-3)}`

Answer 2

`\sf \frac{3}{{z-3} }`

Step-by-step explanation:

`\Longrightarrow \sf (1)/(z) / (z-3)/(3z)`

apply the theorem when
`(a)/(b) / (c)/(d)` then
`(a)/(b) * (d)/(c)`

`\Longrightarrow \sf (1)/(z) * (3z)/(z-3)`

Join the fractions

`\Longrightarrow \sf \frac{3z}{z({z-3)} }`

Cancel out common factor z

`\Longrightarrow \sf \frac{3}{{z-3} }`