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A gas has a volume of 420 L at a temperature of -42.0 degrees celsius. What volume will the gas occupy at 18.0 degrees celsius? Show your work

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Formula

V/T = V1/T1

Givens

V = 430 L

T = - 42 °C = - 42 + 273 = 231°K

V1 = ??

T1 = 18°C + 273 = 291°K

The pressure is a constant.

Solution

420/231 = V1/291 Multiply by 291

420*291 / 231 = V1

V1 = 122220 / 231

V1 = 521.1 L

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