Question

At how many points does the graph of the function intersects the x-axis?

y=2x^-3x+1

A. 0
B.1
C.2

Answer 1

C.2

Explanation:

y=2x^-3x+1

Factor

We know that our only choices are 1*1 and -1*-1 to get 1

We need to get a sum of -3 so I will pick -1 and -1

(2x-1) (x-1)

Check

FOIL

2x^2 -2x-x+1 = 2x^-3x+1

y = (2x-1) (x-1)

0 =(2x-1) (x-1)

Using the zero product property we can find where it crosses the x axis

0 =(2x-1) 0 =(x-1)

2x-1+1 = 0+1 0+1 = x-1+1

2x= 1 1=x

x = 1/2 x=1

There are 2 solutions