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➷ 847) You need to cross multiply
Multiply both sides by (x - 7) and 3
This is what you should get:
![3x- 42 = 2x - 14](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tcqua4mjecomg6am9v3wzd28iv6puiwwcr.png)
Now we just need to get like terms on the same side.
Add 42 to both sides and subtract 2x from both also
Now you get this:
![x = 28](https://img.qammunity.org/2020/formulas/mathematics/college/lp5sxmybcy71m9hkm5x96xylzvbs6pt3s4.png)
848) It's the same principle in this one too.
Multiply both sides by (x - 13) and 11
You should get:
![11x - 132 = 12x - 156](https://img.qammunity.org/2020/formulas/mathematics/middle-school/far5qng8i157dwbv64tj1ak7oyab5az25o.png)
Subtract 11x from both sides and add 156 also
Now you get:
![x = 24](https://img.qammunity.org/2020/formulas/mathematics/middle-school/66fuoi4v7z0c3f81wx9wy1hcfe8a9veeq5.png)
849) Multiply both sides by x
You should get:
![x - 12 = -4x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nkgo12y90294h1cguzbrw56eissek4cvcr.png)
Add 4x to both sides and add 12 also:
![5x = 12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sp8o268e5q1nqkxdoyg6iwrutnwpvy9la4.png)
Divide both sides by 5
![x = 2.4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9sg89l97wvphf2sm651p36mrtn2pxeay8b.png)
850) Multiply both sides by x
You should get:
![x-12 = 4x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n4sdaad1p6344bookyr1svspo0tktss3ls.png)
Subtract x from both sides:
![3x = -12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/p57xns0bfsp50amzmg34e1eg7omp9pmk6x.png)
Divide both sides by 3:
![x=-4](https://img.qammunity.org/2020/formulas/mathematics/college/wvzyemwe3v3nwgy07u4gzjvgd9ub6bpwgv.png)
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ Hannah ♡