Question

What is the solution to the following equation? x2 + 3x + 4 = 0​

Answer 1

`x=(-3\pm \sqrt7i)/(2)`

Explanation:

The given equation is
`x^(2)+3x+4=0`.

We need to find the solution of the above equation.

The solution of an equation
`ax^2+bx+c=0` is :

`x=(-b\pm √(b^2-4ac) )/(2a)`

We have, a = 1, b = 3 and c = 4

`x=(-3+ √((3)^2-4(1)(4)) )/(2), (-3- √((3)^2-4(1)(4)) )/(2)\\\\=(-3+√(9-16))/(2), (-3-√(9-16))/(2)\\\\=(-3\pm \sqrt7i)/(2)`

So, the solution of the given equation is
`(-3\pm \sqrt7i)/(2)`.