Question

If (x)=3x-1 and s(x)=2x+1, which expression is equivalent to r over s (6) ?

Answer 1

`(3(6)-1)/(2(6)+1)`

Explanation:

we have

`r(x)=3x-1`

`s(x)=2x+1`

so

`(r)/(s)(x)=(r(x))/(s(x))=(3x-1)/(2x+1)`

substitute the value of
`x=6` in the expression

`(r)/(s)(6)=(3(6)-1)/(2(6)+1)=(17)/(13)`