Question

Given log8=0.903 and log7=.845, find log8/7

Answer 1

`\bf \textit{Logarithm of rationals} \\\\ \log_a\left( (x)/(y)\right)\implies \log_a(x)-\log_a(y) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log\left( \cfrac{8}{7} \right)\implies \log(8)-\log(7)\implies 0.845-0.903\implies -0.058`

Answer 2

-0.058

Explanation: