Question

Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2 1 x on 2/3

Answer 1

2 1/6

Explanation:

1+1/2+2/3

1 /2 +

2 /3

=

1 × 3+

2 × 3

+

2 × 2

3 × 2

=

3 /6 +4 /6

=

3 + 4 /6

=

1 1/ 6

Answer 2

`2(1)/(6)\approx 2.167` units.

Explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

`\text{Total distance walked by Joy in 3 days}=3*(1)/(3)+(1)/(2)+(2)/(3)`

`\text{Total distance walked by Joy in 3 days}=(1*3)/(3)+(1)/(2)+(2)/(3)`

Let us have a common denominator.

`\text{Total distance walked by Joy in 3 days}=(3*2)/(3*2)+(1*3)/(2*3)+(2*2)/(3*2)`

`\text{Total distance walked by Joy in 3 days}=(6)/(6)+(3)/(6)+(4)/(6)`

`\text{Total distance walked by Joy in 3 days}=(6+3+4)/(6)`

`\text{Total distance walked by Joy in 3 days}=(13)/(6)`

`\text{Total distance walked by Joy in 3 days}=2(1)/(6)`

Therefore, Joy traveled
`2(1)/(6)\approx 2.167` units in 5 days.