Question

Help!!! please what's is the figure​

Answer 1

Hello from MrBillDoesMath!

Answer:

108 cm^2

Discussion:

The area of the logo =

area of Trapezoid on top (I) + area of triangle on bottom (II)

I = (1/2) h ( b1 + b2) h = altitude, b1, b2 = bases

= (1/2) 6 ( 6 + 12)

= (1/2) 6 ( 18)

= 54

II = (1/2) b h

= (1/2) (12) ( 15 - 6) => altitude of triangle = 15 - 6 NOT (1/2) 15

= 54

I + II= 54 + 54 = 108

Thank you,

MrB

Answer 2

Total Area = 108 cm^2

Explanation:

Area Trapezoid

Givens

b1 = 6cm

b2 = 12 cm

h = 6cm

Formula

Area = 1/2 (b1 + b2)*h

Solution

Area = 1/2 (6 + 12)*6

Area = 1/2 18*6

Area = 54 cm^2

Triangle

Givens

b = 12 cm

h = 15 - 6

h = 9

Formula

Area = 1/2 * b * h

Solution

Area = 1/2 * 12 * 9

Area = 54 cm^2

Total Area

Total Area = 54 + 54 = 108 cm^2