2 Answers

Yuriy Kvartsyanyy · Answer 1 · 2020-03-28T04:20:14+0000

Answer : The correct option is, 34 L

Explanation : Given,

Moles of oxygen gas = 1.5 mole

As we know that,

At standard temperature and pressure (STP), 1 mole of gas contains 22.4 liters volume of gas

As, 1 mole of oxygen gas contains 22.4 liters volume of oxygen gas

So, 1.5 mole of oxygen gas contains
$1.5* 22.4=33.6L\approx 34L$ volume of oxygen gas

Therefore, the volume of oxygen gas at standard temperature and pressure (STP) is, 34 L

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