Answer:
![12b^2\sqrt[3]{2a}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7eokn0wiji22du10e99hqdhwq8axo8fidn.png)
Explanation:
Our original expression is
![3b^2(\sqrt[3]{54a})+3(\sqrt[3]{2ab^6})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ma1wxlhupabr20hci4rhnszeobht6nfhus.png)
We will first expand the terms under the cubed roots:
![3b^2(\sqrt[3]{3*3*3*2*a})+3(\sqrt[3]{2a*b*b*b*b*b*b})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3czaps0pn9secrpgv8rorsuzqddd42sr60.png)
Since we have cubed roots, we are looking for groups of 3 factors. In the first term, we have three 3's; this means we can bring a 3 out. In the second term, we have six b's; this means we can bring out 2 b's:
![3b^2(3\sqrt[3]{2a})+3(b^2\sqrt[3]{2a})\\\\=9b^2\sqrt[3]{2a}+3b^2\sqrt[3]{2a}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7112x4dyh4bm0f94f3ausq56g1txfqwm8t.png)
Lastly, combine like terms:
![12b^2\sqrt[3]{2a}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7eokn0wiji22du10e99hqdhwq8axo8fidn.png)