Question

Which equation can be used to represent "six added to twice the sum of a number and four is equal to one-half of

the difference of three and the number"?
O6 + 2(x + 4) = (3-x)
O 6+ 2(x+4)=(x-3)
O (6+2)(x+4)=(3-x)
O (6+2)(x+4)=(x-3)

Answer 1

Explanation:

Comment

Start with the right hand side.

1/2(3 - x)

This reads as The difference between 3 and a number. You put it the way you read it difference between 3 and a number = 3 - x The 1/2 affects both terms. So that makes b and d incorrect.

The left side is a bit harder. You want the sum of 6 + something. Read the rest of the given

6 + 2(x +4)

Now that is all equal to

6 + 2(x + 4) = 1/2 (x - x)

The answer is A