36,122 views
22 votes
22 votes
Find the distance between (0,3) and (0,-6)

User HenryM
by
2.4k points

2 Answers

21 votes
21 votes

Answer: 9

Explanation:

let the two points P (0,3) and Q(0,-6)

We need to find distance PQ

PQ=
√((x2-x1)^2+(y2-y1)^2)

here

x1=x coordinate of P=0

y1=y coordinate of P=3

x2=x coordinate of Q=0

y2=y coordinate of Q=-6

Putting values


PQ=√((0-0)^2+(-6-3)^2)\\
PQ=√((0)^2+(-9)^2) \\PQ=√(81) \\PQ=9

User Asymptote
by
2.8k points
24 votes
24 votes

Answer:

the answer should be 9

Explanation:

,look at a graph count from 0,-6 up to 0,3 . the distance between them is 9

User Wardw
by
3.7k points