Question

Plz help! Number 6 please!

Answer 1

The last 2 statements are true

Explanation:

given f(x) = x² + 6x and g(x) = 2x³

f(x) × g(x) = 2x³(x² + 6x) = 2
`x^(5)` + 12
`x^(4)`

not 2
`x^(5)` + 12x³

f(0) = 0 + 0 = 0 and g(2) = 2 × 2³ = 2 × 8 = 16

f(0 × g(0) = 0 × 16 = 0 ≠ 16

f(1) = 1 + 6 = 7 and g(1) = 2 × 1³ = 2

f(1) × g(1) = 7 × 2 = 14 ← True

g(x) × g(x) = 2x³ × 2x³ = 4
`x^((3+3))` = 4
`x^(6)` ← True

Answer 2

Answer: (C) f(1)·g(1) = 14 and (D) g(x)·g(x) = 4x⁶

Explanation:

f(x) = x² + 6x g(x) = 2x³

f(x) · g(x) = (x² + 6x)( 2x³)

= 2x⁵ + 12x⁴ not equal to 2x⁵ + 12x³ (FALSE)

f(0) = 0² + 6(0) g(2) = 2(2)³

= 0 + 0 = 2(8)

= 0 = 16

f(0) · g(2) = 0 · 16

= 0 not equal to 16 (FALSE)

f(1) = 1² + 6(1) g(1) = 2(1)³

= 1 + 6 = 2(1)

= 7 = 2

f(1) · g(1) = 7 · 2

= 14 equal to 14 (TRUE)

g(x) · g(x) = (2x³)(2x³)

= 4x⁶ equal to 4x⁶ (TRUE)