Question

Manny collected 4 times as many shells than Cameron together the collected 40 how many shells did manny collect jdhhtfhkjgddyjjhhjfsdgjj

Answer 1

1) Make an equation:

`4x + x = 40`

Where x represents the unknown amount (the number of shells)

2) Solve for x

`5x = 40`

Combine the x's

`x = 8`

Divide 40 by 5 to get X alone

3) Answer:

Manny collected 32 seashells, while Cameron only collected 8

Answer 2

Based on the given problem, we know that Cameron and Manny together collected 40 shells and that Manny collected 4 times more shells than Cameron.

Let's denote the number of shells Cameron collected as 'c' and the number of shells Manny collected as 'm'. From what we're given, we can create two equations.

The first is that the total shells they both collected is 40, so this can be written as: c + m = 40.

The second equation is that Manny collected 4 times more than Cameron, so this can be written as: m = 4c.

Now we need to solve this system of equations to find 'c' and 'm'.

Using the equation m = 4c, we can replace 'm' in the first equation (c + m = 40) with '4c'. When we do this we have c + 4c = 40. This simplifies to 5c = 40.

Solving for 'c', if we divide both sides of the equation by 5 results in c = 8.

Now that we have found 'c', we can find 'm'. Using the equation m = 4c, we can replace 'c' with 8 to get m = 4*8. This results in m = 32.

So, Cameron collected 8 shells and Manny collected 32 shells.