Question

A car moving at a velocity of 25 m/s, accelerates at a rate of 6 m/s find its velocity after 3s

Answer 1

The answer would be:

`43(m)/(s)`

Here is why:

To determine what the final velocity is, we can do this by using the kinematics formula:

`V_(f)=V_(i) +at`

Where:

Vf = final velocity

Vi = initial velocity

a = acceleration

t = time

In this case, the following are your given:

Vf = unknown

Vi = 25 m/s

a = 6 m/s²

t = 3 s

So just plug that in the equation and solve:

`V_(f)=V_(i) +at`

`V_(f)=25(m)/(s) +(6 (m)/(s^(2)))(3s)`

`V_(f)=25(m)/(s) +18 (m)/(s)`

`V_(f)=43(m)/(s)`

So the answer is 43m/s