Answer:
The length of the longer base is 80 feet.
Explanation:
We are given that county courthouse is shaped like a trapezoid.
Let the height of the court house be h
Since we are given that The shorter base of the trapezoid is 15 feet longer than the height.
So, the shorter base = h+15
We are also given that The longer base is 5 feet longer than 3 times the height
So, longer Base = 3h+5
Now we are also given that the area of the landing is 1500 square feet.
Formula of area of trapezium :
=
![(1)/(2) *(\text{Length of longer base}+\text{Length of shorter base})*height](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6c6ftd2eru1135zqiotlbt29jcbksgnfzj.png)
Substituting the values .
![1500=(1)/(2) *(h+15+3h+5)*h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w8kymxgbu1kklrebhtkfud1567wac00r3k.png)
![1500=(1)/(2) *(4h+20)*h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y304h2o3mlqex6di0mqv69dewep6x415vw.png)
![1500*2=(4h+20)*h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y7gse1hmz0yj7pfodg9hvay1rs7obuxilq.png)
![3000=4h^2+20h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/twhms9cifvrtzr0wa89tnmxfcnj4ulpdn8.png)
Taking 4 common from the equation.
![750=h^2+5h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zkla64kjzotro8z9hu5zw3z7dm0ovwp3lc.png)
![h^2+5h-750=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/izygtzsfubthpxc2v6p0vfljq4d8jcffiq.png)
![h^2-25h+30h-750=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rsqn9ptulxl623wer8ylzftucfcfc338vu.png)
![h(h-25)+30(h-25)=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6xggijvyfbdgncprewh7yrqpz7nj4bu35b.png)
![(h-25)(h+30)=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n3nd04pctjzrlgkj35ofde43cwzbnjtb3a.png)
⇒ h = 25, -30
Neglect the negative value .
So, height = 25 feet.
Length of Longer base = 3h+5 =3*25+5=80 feet
Hence , the length of the longer base is 80 feet.