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27 votes
27 votes
A roller coaster's velocity at the bottom of a hill is 35.0 m/s, 5.00 seconds later it reaches the top of the hill with a velocity of 10.0

m/s. What was the deceleration of the coaster?
O 5.00 m/s/s
O 7.00 m/s/s
O 2.00 m/s/s
O 25.0 m/s/s

User Ilya Tretyakov
by
2.9k points

1 Answer

29 votes
29 votes

Answer:

5 m /s^2

Step-by-step explanation:

Change in velocity = 35 - 10 = 25 m/s

change in time = 5 s

decelleration = 25/5 = 5 m/s^2

User Jason Rogers
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3.2k points