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PLEASE HELP ME I BEG

CSC(X)^4-COT(X)^4=2CSC(X)^2-1
you need to get one side to look like the other
one rule: you cant touch the side you are trying to get it to look like
(SOLVED IT)

User Drlobo
by
5.3k points

1 Answer

3 votes

Answer:

see explanation

Explanation:

Using the trigonometric identity

• 1 + cot²x = csc²x

Consider the left side


csc^(4) x -
cot^(4) x

Factorise as a difference of squares

= (csc²x - cot²x)(csc²x + cot²x)

= (1 + cot²x - cot²x)(csc²x + cot²x)

= csc²x + cot²x

= csc²x + csc²x - 1

= 2csc²x - 1 = right side ⇒ verified




User Sephy
by
4.4k points