Question

a helium balloon has a volume of 2.00 L at 101 kPa. As the balloon rises, the pressure drops to 97.0 kPa. what is the new volume?​

Answer 1

Answer: The new volume is 2.1 L.

Step-by-step explanation:

Use the formula Boyle's law.

`P_(1)V_(1)=P_(2)V_(2)`

Here,
`P_(1), P_(2)` are the initial pressure and the final pressure and
`V_(1),V_(2)` are the initial and the final volumes.

As, it is given in the problem, a helium balloon has a volume of 2.00 L at 101 kPa. As the balloon rises, the pressure drops to 97.0 kPa.

`P_(1)V_(1)=P_(2)V_(2)`

Put P_{1}=101 kPa,V_{1}=2.00L and P_{2}=97.0 kPa.

`(101 )(2.00)=(97.0)V_(2)`

`V_(2)=((101)(2.00))/(97)\\V_(2)=2.1 L`

Therefore, the new volume is 2.1 L.