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there are 3 consecutive even integers .if twice the first integer added to the third is 268,222, find all three integers

2 Answers

6 votes

Answer:

89,408 89,410 89,412

Explanation:

there are 3 consecutive even integers .if twice the first integer added to the third-example-1
User Leonardo Lobato
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8.3k points
5 votes

Answer:

89406, 89408 and 89410.

Explanation:

Let n be the any even integer.

So n+2 will be 2nd even integer and n+4 will be 3rd even integer.

We are told that twice the first integer added to the third is 268,222.

Twice the first integer will be 2*n.

We can represent this information in an equation as:


2n+(n+4)=268222


2n+n+4=268222


3n+4=268222

Let us subtract 4 from both sides of our equation.


3n+4-4=268222-4


3n=268218

Let us divide both sides of our equation by 3.


(3n)/(3)=(268218)/(3)


n=89406

Therefore, our 1st even integer will be 89406.

2nd even integer = n+2


n+2=89406+2=89408

3rd even integer = n+4


n+4=89406+4=89410

Therefore, our three consecutive even integers will be 89406, 89408 and 89410.

User Marc Balmer
by
8.0k points

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