The correct answer is 4.4 ml.
The mass of thallium required = 8.0 × 10² mg = 0.8 g
Molarity = 0.45 M
The moles of thallium can be determined by the formula mass / atomic mass
= 0.8 g / 204.38 g/mol
= 0.00391 moles
One mole of thallium sulfate gives two moles of thallium,
So, the number of moles of thallium needed = 0.00391 / 2 = 0.00196 moles
Volume of solution needed = moles / molarity
= 0.000196 moles / 0.45 M
= 4.35 ml or 4.4 ml