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1. Fe + S FeS

2. H₂ + Cl₂ HCl

3. Mg + O₂ MgO

4.O₂ + H₂ H₂O

5. Hg0 Hg + O₂

6.Ca + H₂O Ca(OH)₂ + H₂

7.CH₄ + O₂ CO₂ + H₂O

1. Fe + S FeS 2. H₂ + Cl₂ HCl 3. Mg + O₂ MgO 4.O₂ + H₂ H₂O 5. Hg0 Hg + O₂ 6.Ca + H-example-1
User IgorDiy
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6.2k points

1 Answer

5 votes

Answers:

1. Fe + S → FeS

2. H₂ + Cl₂ → 2 HCl

3. 2 Mg + O₂ → 2 MgO

4. O₂ + 2 H₂ → 2 H₂O

5. 2 HgO → 2 Hg + O₂

6. Ca + 2 H₂O → Ca(OH)₂ + H₂

7. CH₄ + 2 O₂ → CO₂ + 2 H₂O


Step by step solution:

1. Fe + S → FeS

In this chemical equation we have:

On the left side: On the right side:

Fe: 1 atom Fe: 1 atom

S: 1 atom S: 1 atom

We have the same quantity of atoms on both sides of the equation, then the equation is balanced.


2. H₂ + Cl₂ → HCl

In this chemical equation we have:

On the left side: On the right side:

H: 2 atoms H: 1 atom

Cl: 2 atoms Cl: 1 atom

The equation is not balanced.

If we multiply the molecule of HCl on the right side of the equation by 2, we would get 2 H atoms and 2 Cl atoms on the right side:

H₂ + Cl₂ → 2 HCl


3. Mg + O₂ → MgO

In this chemical equation we have:

On the left side: On the right side:

Mg: 1 atom Mg: 1 atom

O: 2 atoms O: 1 atom

The equation is not balanced.

To get 2 O atoms on the right side of the equation, we must multiply the molecule of MgO by 2:

Mg + O₂ → 2 MgO

Now we have 2 Mg atoms on the right side, then we must multiply by 2 Mg on the left side of the equation:

2 Mg + O₂ → 2 MgO


4. O₂ + H₂ → H₂O

In this chemical equation we have:

On the left side: On the right side:

O: 2 atoms O: 1 atom

H: 2 atoms H: 2 atoms

The equation is not balanced.

To get 2 O atoms on the right side, we must multiply the molecule of H₂O

by 2:

O₂ + H₂ → 2 H₂O

Now we have 2(2)=4 H atoms on the right side and only 2 H atoms on the left side, then we must multiply the molecule of H₂ on the left side by 2:

O₂ + 2 H₂ → 2 H₂O


5. HgO → Hg + O₂

In this chemical equation we have:

On the left side: On the right side:

Hg: 1 atom Hg: 1 atom

O: 1 atom O: 2 atoms

The equation is not balanced.

To get 2 O atoms on the left side, we must multiply the molecule of HgO

by 2:

2 HgO → Hg + O₂

Now we have 2 Hg atoms on the left side and only 1 Hg atom on the right side, then we must multiply Hg on the left side by 2:

2 HgO → 2 Hg + O₂


6. Ca + H₂O → Ca(OH)₂ + H₂

In this chemical equation we have:

On the left side: On the right side:

Ca: 1 atom Ca: 1 atom

H: 2 atoms H: 2+2=4 atoms

O: 1 atom O: 2 atoms

The equation is not balanced.

To get 2 O atoms on the left side, we must multiply the molecule of H₂O by 2:

Ca + 2 H₂O → Ca(OH)₂ + H₂

And we get 2(2)=4 H atoms on the left side. The equation is balanced.


7. CH₄ + O₂ → CO₂ + H₂O

In this chemical equation we have:

On the left side: On the right side:

C: 1 atom C: 1 atom

H: 4 atoms H: 2 atoms

O: 2 atoms O: 2+1=3 atoms

The equation is not balanced.

To get 4 H atoms on the right side, we must multiply the molecule of H₂O by 2:

CH₄ + O₂ → CO₂ + 2 H₂O

Now we have 2 O atoms on the left side, and 2+2=4 O atoms on the right side, then we must multiply the molecule of O₂ on the left side by 2:

CH₄ + 2 O₂ → CO₂ + 2 H₂O


User Dangowans
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