Question

Help with 1 2 and 3 please

Answer 1

1. Amperes, is the SI unit (also a fundamental unit) responsible for current.

2.
`I = (q)/(t)` Δq over Δt technically

Rearrange for Δq

I x Δt = Δq

1.5mA x 5 = Δq

Δq = 0.0075

Divide this by the fundamental charge "e"

Electrons: 0.0075 / 1.60 x 10^-19

Electrons: 4.6875 x 10^16 or 4.7 x 10^16

3. So we know that the end resistances will be equal so:

ρ = RA/L

ρL = RA

ρL/A = R

Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper

`(p1L1)/(A1)  = (p2L2)/(A2)\\`

We are looking for L2 so we can isolate using algebra to get:

`(A2((P1L1)/(A1)) )/(P2) = L2`

If you fill in those values you get 0.0205

or 2.05 cm