Question

How many possible combinations would there be for a-z, with a 4 character limit.

I tried 4^26, but that was not a correct answer. How would I go about correctly solving this?

Answer 1

Hello from MrBillDoesMath!

Answer:

26^4

Discussion:

Each of the 4 characters belong to the 26-character set {a.b...,z}. Therefore the number of combinations is 26^4 ( = 456,976)

Thank you,

MrB