Answer:
x=33
Explanation:
8^(x+7) = 32^(x-9)
Rewriting 8 as 2^3 and 32 as 2^5
2^3 ^(x+7) = 2^5^(x-9)
We know that a^b^c = a^(b*c)
2^(3*(x+7)) = 2^(5*(x-9))
2^(3x+21) = 2^(5x-45)
We know that if the bases are the same, the exponents are the same
3x+21 = 5x-45
Subtract 3x from each side
3x-3x+21 = 5x-3x-45
21 = 2x-45
Add 45 to each side
21+45 = 2x-45+45
66= 2x
Divide by 2
66/2 = 2x/2
33=x