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how many calories are required to raise the temperature of 225g of water from 42 degrees Celsius to 75 degrees​

User Inntran
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2 Answers

4 votes

Final answer:

To raise the temperature of 225g of water from 42°C to 75°C, it requires 7425 calories. This is calculated using the specific heat capacity of water which is 1 calorie/gram°C, and the temperature change of 33°C.

Step-by-step explanation:

To calculate how many calories are required to raise the temperature of 225g of water from 42 degrees Celsius to 75 degrees Celsius, you need to use the concept of specific heat capacity. The specific heat capacity of water is 1 calorie/gram°C, which is the amount of heat needed to raise the temperature of 1 gram of water by 1°C.

To find the total heat required, use the formula:

Heat (cal) = Mass (g) × Specific Heat Capacity (cal/g°C) × Change in Temperature (°C)

For this problem:

  • Mass (m) = 225g
  • Specific Heat Capacity (c) = 1 cal/g°C (for water)
  • Change in Temperature (ΔT) = 75°C - 42°C = 33°C

Plugging these values into the formula:

Heat = 225g × 1 cal/g°C × 33°C

Heat = 7425 calories

Therefore, it takes 7425 calories to raise the temperature of 225g of water from 42°C to 75°C.

User Bmiller
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5.7k points
4 votes

the answer would be 342, how I got this answer? well i just added all the numbers in....

hope this helps though! C:

User Pearpages
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