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21 votes
21 votes
What is the point-slope form of a line with slope 3/2 that contains the point

(-1, 2)?

A.y+2=(x + 1)
B. y-2-(x-1)
C. y+2=(x-1)
D. y-2-(x+1)

User JesseBoyd
by
2.6k points

2 Answers

15 votes
15 votes

y - 2=(x+1) , or D because its rlly simple u just need to ask someone else for help.
User Tadamson
by
3.2k points
18 votes
18 votes

Answer:


  • \boldsymbol{\rm{y-2=(3)/(2)(x+1)}}, or D

Explanation:

Hello

If a line's equation has the form
\boldsymbol{\rm{y-y1=m(x-x1)}}, then it's considered to be in point-slope form.

In that formula,


  • \boldsymbol{\rm{y1}} is the y co-ordinate (2nd co-ordinate) of the point (here it's given as 2)

  • \boldsymbol{\rm{m}} is the slope, here it's 3/2

  • \boldsymbol{\rm {x1}} is the x co-ordinate (the first co-ordinate) of the point.

Now you know why this equation is called point-slope form!

Now that we're familiar with the equation, let's plug in the information that's given to us...


\boldsymbol{\rm{y-2=\displaystyle(3)/(2)(x-(-1)}} | simplify


\boldsymbol{\rm{y-2=\displaystyle(3)/(2)(x+1)}}


\pmb{\tt{done~!!}}


\orange\hspace{300pt}\above3

User Rushikesh Bharad
by
3.0k points
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