Question

For
`f(x) = 4x +1` and
`g(x) = x^(2) - 6`, find
`((f)/(g))(x)`.

Answer 1

Choice B is correct answer.

Explanation:

From question statement, we observe that

Two binomial functions are given and we have to find quotient function.

f(x) = 3x+1 and g(x) = x²-6

(f/g)(x) = ?

(f/g)(x) = 3x+1 / x²-6

If x²-6 = 0 ⇒ x = ±√6 , then (f/g)(x) is not defined.

hence, solution is 3x+1 / x²-6 , x ≠ ±√6.

Answer 2

Answer: Our required function becomes

`(f(x))/(g(x))=(3x+1)/(x^2-6)\\\\x\\eq \pm√(6)`

Explanation:

Since we have given that

`f(x)=3x+1\\\\g(x)=x^2-6`

We need to write in quotient form i.e.
`(f(x))/(g(x))`

So, our function becomes,

`(f(x))/(g(x))=(3x+1)/(x^2-6)\\\\x\\eq \pm√(6)`

Hence, our required function becomes

`(f(x))/(g(x))=(3x+1)/(x^2-6)\\\\x\\eq \pm√(6)`