Question

Solve the following system of equation by using the elimination method 3x-y=12 and -3x+5=-4

Answer 1

Given the system of equation:

`3x-y=12` .....[1]

`-3x+5y= -4` .....[2]

Adding equation [1] and [2] to eliminate x we have;

`(3x-y)+(-3x+5y) = 12-4`

`3x-y-3x+5y= 8`

Combine like terms;

`4y= 8`

Divide both sides by 4 we get;

y = 2

Substitute the value of y in [1] we get;

3x-2= 12

Add 2 to both sides we get;

3x = 14

Divide both sides by 3 we get;

x = 4.67

Therefore, the solution for this system of equation is, (4.67, 2)