Question

4x2 - y2 = 16 The value of b is
A. 1
B.2
C.4
D.16

Answer 1

Option C.
`b=4`

Explanation:

we know that

The equation of a hyperbola with a horizontal transverse axis is

`(x^(2))/(a^(2))-(y^(2))/(b^(2))=1`

In this problem we have

`{4x^(2)}-{y^(2)}=16`

Divide by 16 both sides

`(4x^(2))/(16)-(y^(2))/(16)=1`

`(x^(2))/(4)-(y^(2))/(16)=1`

so

`b^(2)=16`

`b=4`